MATHS-OBJ 1CBCDACDCCD 11AADBDACBBC 21BDDABDADAD 31CDACCCCCDA 41BBBCDCACDB Completed. ====== FOR TOMORROW'S PAPER SEND 500MTN TO 09066669882 AND YOUR NAME ============ THEORY – ANSWERS Always subscribe with us to get your accurate questions and answers A1 GUARANTEED 09066669882 ...... (1a) Given A={2,4,6,8,...} B={3,6,9,12,...} C={1,2,3,6} U= {1,2,3,4,5,6,7,8,9,10} ... A' = {1,3,5,7,9} B' = {1,2,4,5,7,8,10} C' = {4,5,7,8,9,10} A'nB'nC' = {5, 7} ... (1b) Cost of each premiere ticket = $18.50 At bulk purchase, cost of each = $80.00/50 = $16.00 Amount saved = $18.50 - $16.00 =$2.50 ... 2ai). p = (rk/Q -ms)2/3 p3/2 = (rk/Q -ms)2/8 * 3/2 p3/2 = rk/Q = ms p3/2 + ms = rk/Q q(p3/2 + ms ) = rk Q =rk/p3/2 + ms ... 2aii) Where : r = 10, k = 4, s = 0.2 p = 3, m = 15 ... Q = 10 * 4/3^3/2 + (15 * 0.2) Q = 40/5.2 + 3 Q = 40/8.2 Q = 4.88 ... (5a) Total income = 32+m+25+40+28+45 =170+m PR(²)=m/170+m = 0.15/1 M=0.15(170+m) M=25.5+0.15m 0.85m/0.85=...
7a)
A) T3=6 & T7 =30
I)common difference using Tn=a+(n-1)d
In the 3rd term; n =3
=>T3=a+(3-1)d=6
=>a+2d=6 equation (1)
In the 7th term ;n =7
=> T7=a+(7-1)d=30
=>a + 8d=30 equation (1) & (2)
Simultaneous
A+2d =6 equation (1)
A+ 8d=30 equation (2)
0+(1-6d) =-24
=> -6d= -24
=>d = -24/-6 =4
II) first term put d=4 into equation
Eng NASERDAHER 💪🏻💪🏻💪🏻
Discount percent =15%
Discount amount =#600
Actual amount paid on the article =?
Original amount on the article =*
15%*=#600
15/100* =600
15*=600*100
15*=60000
*=60000/15
*=#4,000
Therefore actual amount paid on the article
=#4,000-#600
=#3,400
Actual amount paid on the article =#3,400
1a)
Log 10(20*-10)-log10(*+3)=log105
(20*-10/*+3)=log10 =5
20*-10/*+3=5
5(*+3)=20*-10
5*+15=20*-10
15+10=20*-5*
25=15*
*=25/15
*=5/3=1 2/3
1b
ENG NASER DAHER 💪🏻💪🏻💪🏻💪🏻
No 4(i)
length of Arc of the sector
Titter= 72?, r = 14cm
L= titter / 360 x 2 pie r
==> L= 72/360 x 2 x 22/7 x 14
=44352/2520 = 17.6cm
(ii) perimeter of the sector
Perimeter = titter/360 x 2 pie r + 2r = 17.6 +(2x14) =17.6+28= 45.6cm
(iii) Area of the sector
Area = Titter/360 x pie r? =
72/360 x 22/7 x (14)? = 72 x 22 x 196/2520
Area= 310464/2520 = 123.2cm?
I still remain ENGR NASER DAHER 💪🏻💪🏻💪🏻💪🏻💪🏻💪🏻💪🏻
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