2020 mathematics answer
MATHS-OBJ
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11AADBDACBBC
21BDDABDADAD
31CDACCCCCDA
41BBBCDCACDB
Completed.
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(1a)
Given A={2,4,6,8,...}
B={3,6,9,12,...}
C={1,2,3,6}
U= {1,2,3,4,5,6,7,8,9,10}
FOR TOMORROW'S PAPER SEND 500MTN TO 09066669882 AND YOUR NAME============ THEORY – ANSWERS Always subscribe with us to get your accurate questions and answers A1 GUARANTEED 09066669882 ......
...A' = {1,3,5,7,9} B' = {1,2,4,5,7,8,10} C' = {4,5,7,8,9,10} A'nB'nC' = {5, 7}
...(1b) Cost of each premiere ticket = $18.50 At bulk purchase, cost of each = $80.00/50 = $16.00 Amount saved = $18.50 - $16.00 =$2.50
...2ai). p = (rk/Q -ms)2/3 p3/2 = (rk/Q -ms)2/8 * 3/2 p3/2 = rk/Q = ms p3/2 + ms = rk/Q q(p3/2 + ms ) = rk Q =rk/p3/2 + ms
...2aii) Where : r = 10, k = 4, s = 0.2 p = 3, m = 15
...Q = 10 * 4/3^3/2 + (15 * 0.2) Q = 40/5.2 + 3 Q = 40/8.2 Q = 4.88
...(5a) Total income = 32+m+25+40+28+45 =170+m PR(²)=m/170+m = 0.15/1 M=0.15(170+m) M=25.5+0.15m 0.85m/0.85=25.5/0.85 M=30
....(5b) Total outcome = 170 + 30 = 200
...(5c) PR(even numbers) = 30+40+50/200 =115/200 = 23/40
....5a) Using elimination method 2x: 2p-4q=4 3x: 4p+2q=9
....Hence 4p-6q=8 9p+6 =27 Adding equation (i) to (ii) Therefore 13p=35
...Thus p=35/13 Substituting P=35/13 in equation (ii) Hence 3p+2q=9........... (ii) 3(35/13) + 2q= 9 =105/13+2q=9 Multiplying throughout by 13 ~13~ *105/ ~13~ + ~13~*2q =13*9 Thus 105+26q=117 Collecting like terms 26q =117-105 26q=12 Q=12/26 or 6/13
..(7a) Click here to view image Using Pythagoras theorem, l²=48² + 14² l²=2304 + 196 l²=2500 l=√2500 l=50m Area of Cone(Curved) =πrl Area of hemisphere=2πr² Total area of structure =πrl + 2πr² =πr(l + 2r) =22/7 * 14 [50 + 2(14)] =22/7 * 14 * 78 =3432cm² ~3430cm² (3 S.F)
..(b) let the percentage of Musa be x Let the percentage of sesay be y x + y=100 -------------------1 (x - 5)=2(y - 5) x - 5=2y - 10 x - 2y=-5 -------------------2 Equ (1) minus equ (2) y - (-2y)=100 - (-5) 3y=105 y=105/3 y=35 Sesay's present age is 35years
....8a) Cost price = Ghd 150 Let the number of plates be X profit per one = 1 GHd Total profit = 6 GHd Remaining plates = x - 4 Total profit = (x - 4) 1Ghd 6 = x - 4 X = 6 + 4 X = 10
engr Naser daher solution(9a) Draw the triangle
...(9b) (i)Using cosine formulae q² = x² + y² - 2xycosQ q² = 9² + 5² - 2×9×5cos90° q² = 81 + 25 - 90 × 0 q² = 106 q = square root 106 q = 10.30 = 10km/h Distance = 10 × 2 = 20km
..(ii) Using sine formula y/sin Y = q/sin Q 5/sin Y = 10.30/sin 90° Sin Y = 5 × sin90°/10.30 Sin Y = 5 × 1/10.30 Sin Y = 0.4854 Y = sin‐¹(0.4854), Y = 29.04 Bearing of cyclist X from y = 90° + 19.96° = 109.96° = 110°
..(9c) Speed = 20/4, average speed = 5km/h The number of plates is 10 11b) 8y = - 4x + 24 Y = - 4/8 x + 24/8 Y = - 1/2 x + 3 Gradient = m = - 1/2 :. Y- y1 = m(x-x) Y- 12 = 1/2 (x + 8) 2(y-12) = 1 (x+8) 2y - 24 = -x-8 X + 2y - 24 + 8 = 0 X + 2y - 24 + 8 = 0 X + 2y - 16 = 0 Is the line above 11b) 8y = - 4x + 24 Y = - 4/8 x + 24/8 Y = - 1/2 x + 3 Gradient = m = - 1/2 :. Y- y1 = m(x-x) Y- 12 = 1/2 (x + 8) 2(y-12) = 1 (x+8) 2y - 24 = -x-8 X + 2y - 24 + 8 = 0 X + 2y - 24 + 8 = 0 X + 2y - 16 = 0 Is the line above ===================== (5a) Total income = 32+m+25+40+28+45 =170+m PR(²)=m/170+m = 0.15/1 M=0.15(170+m) M=25.5+0.15m 0.85m/0.85=25.5/0.85 M=30 (5b) Total outcome = 170 + 30 = 200 (5c) PR(even numbers) = 30+40+50/200 =115/200 = 23/40 👇👇👇Nigeria 🇳🇬 4a) Total Surface Area = 224πcm² r:l = 2:5 r/l = 2/5 Cross multiply 2l/2 = 5r/2 L = 5r / 2 Total surface = πrl + πr² = πr (l + r) 24π/π = πr (5r/2 + r )/ π 224 = 5r²/2 + r²/1 L.c.m = 2 448 = 5r² + 2r² 448 / 7= 7r²/7 r² = 64 r = √64 = 8cn L = 5*8/2 = 20cm 4b) Volume = 1/2πr²h = 1/3 * 22/7 * 8 * 8 * 18.33 = 1228.98cm³ L² = h² + r ² 20² = h² + 8² 400 - 64 = h² h² = 336 h = √ 336 h = 18.33cm
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