MATHS-OBJ 1CBCDACDCCD 11AADBDACBBC 21BDDABDADAD 31CDACCCCCDA 41BBBCDCACDB Completed. ====== FOR TOMORROW'S PAPER SEND 500MTN TO 09066669882 AND YOUR NAME ============ THEORY – ANSWERS Always subscribe with us to get your accurate questions and answers A1 GUARANTEED 09066669882 ...... (1a) Given A={2,4,6,8,...} B={3,6,9,12,...} C={1,2,3,6} U= {1,2,3,4,5,6,7,8,9,10} ... A' = {1,3,5,7,9} B' = {1,2,4,5,7,8,10} C' = {4,5,7,8,9,10} A'nB'nC' = {5, 7} ... (1b) Cost of each premiere ticket = $18.50 At bulk purchase, cost of each = $80.00/50 = $16.00 Amount saved = $18.50 - $16.00 =$2.50 ... 2ai). p = (rk/Q -ms)2/3 p3/2 = (rk/Q -ms)2/8 * 3/2 p3/2 = rk/Q = ms p3/2 + ms = rk/Q q(p3/2 + ms ) = rk Q =rk/p3/2 + ms ... 2aii) Where : r = 10, k = 4, s = 0.2 p = 3, m = 15 ... Q = 10 * 4/3^3/2 + (15 * 0.2) Q = 40/5.2 + 3 Q = 40/8.2 Q = 4.88 ... (5a) Total income = 32+m+25+40+28+45 =170+m PR(²)=m/170+m = 0.15/1 M=0.15(170+m) M=25.5+0.15m 0.85m/0.85=...
WAEC GCE MATHEMATICS THEORY AND OBJECTIVES (2018
Our work is to DELIVER COMFIRMED AND VERIFIED
WAEC
JAMB
NECO
NABTEB
BECE
ANSWERS
_OBJ LOADING_
(1a)
S = ½n[a + L]
Where S = 130
S = n/2[a+a+(n-1)d]
2S = n[2a+(n-1)d]
2(130) = 10[2a + (10 - 1)d]
260 = 10[2a + 9d]
260 = 20a + 90d .....(I)
a + 4d = 3a...... (II)
4d = 3a - a
4d = 2a
2d = a...... (III)
Substitute a = 2d into Eqn (I)
260 = 20(2d) + 90d
260 = 40d + 90d
260 = 130d
260/130 = 130d/130
d = 2
Hence common difference d = 2
Engr NASER DAHER 09030302775
(1b)
First term a = 2d = 2(2) = 4
(1c)
L = a+(n-1)d
28 = 4+(ń - 1)2
28 = 4+2n - 2
2n = 28 - 2
2n = 26
2n/2 = 26/2
n = 13
(4a)
(2y+x) + (6y-2x+1) + 4y = 28 ...(i)
6y-2x + 1 = 4y... (II)
2y+ x +6y - 2x + 1 +4 = 28
12y + x +6 -2x + 1 + 4 = 28
12y - x + 1 = 28
12y - x = 29... (III)
6y-2x + 1 = 4y, 6y-2x - 4y = 1
2y - 2x = -1... (iv)
24y - 2x = 54
2y - 2x = 1
22y/2w = 55/22 y = 2.5
12y - x = 27
12 (2.5) - x = 27
30 x 27 x=3
(b)
2y + x = 2 (2.5) + 3 = 5+3 = 8cm
6y - 2x + 1 = (2.5)-2 (3) + 1
= 15-6 + 1 = 10cm
4y = 4(2.5) = 10cm
www.mrwhyhurry.blospot.com
___________________________________________________
5a)5-x > 1
5-x >1
5-1>x
4>x
(5a)
5 - X > 1 9 + X >_ 8
5 - 1 > X X >_ 8 - 9
6 > X X >_ -1
Range is
-1_< X < 6 OR 6 >X >_ -1
(5b)
PQR + PSR = 180(supplementary angles of a cyclic quad)
PQR + 56 = 180
PQR = 180 - 56
PQR = 124°
Next, join P to R
QRP = QPR(base angles of an isosceles)
PQR + 2QRP = 180(Sum of angles in a triangle)
124 + 2QRP = 180
2QRP = 56°
QRP = 56/2 = 28°
PRS = 90°(angle in a semi - circle)
= 28 + 90
= 118°
www.mrwhyhurry.blospot.com
And 9-x>or equals to 8
9-8>or equals to X
1>or equals to x
Therefore 4>x and 1>or equals to x
Final answer.
4>x
Comments
autoketing
Create Discount master
Product discount app
autoketing
sales pop master
sales pop master online
shell shockers games
duck life space games
You know what? I really like your posts. I wander on the internet to find something new or unique. And I see your articles. I decided to linger at your site and read more and more. I hope that you can upload new posts. I will be the first one to read them. Thanks a million
gy y games
Games of friv
y8 soccer
io jogos 2019
free online friv Games
Thank you so much for taking time to make this very informative and interesting site. I have learned many blogs from your site that is really so interesting.